Final answer:
The equation of the line passing through (-2, -1) that is parallel to 3x - 5y = 11 is y = (3/5)x + 7/5.
Step-by-step explanation:
The equation of the line passing through (-2, -1) that is parallel to 3x - 5y = 11 can be found by using the concept of parallel lines. Two lines are parallel if they have the same slope. The given equation 3x - 5y = 11 is in the form of y = mx + b, where m is the slope. We can rearrange the equation to find the slope, which is 3/5. So, the parallel line will also have a slope of 3/5.Using the point-slope form of a linear equation, y - y1 = m(x - x1), where (x1, y1) is a given point on the line, we plug in the values (-2, -1) and the slope 3/5 to find the equation of the line: y - (-1) = (3/5)(x - (-2)). Simplifying this equation, we get y = (3/5)x + 7/5. Therefore, the equation of the line passing through (-2, -1) that is parallel to 3x - 5y = 11 is y = (3/5)x + 7/5.