Question

Consider a parallel plate capacitor having plates of area 1.6 cm² that are separated by 0.012 mm of neoprene rubber. You may assume the rubber has a dielectric constant -κ = 6.7. What is the capacitance of the capacitor?

Answer 1

The capacitance of the parallel plate capacitor is approximately 9.31 x 10⁻¹² F.

Step-by-step explanation:

The capacitance of a parallel plate capacitor can be calculated using the formula:

C = (κ * ε0 * A) / d

where C is the capacitance, κ is the dielectric constant, ε0 is the permittivity of free space, A is the area of the plates, and d is the separation between the plates.

Given that the area of the plates is 1.6 cm², the separation between the plates is 0.012 mm, and the dielectric constant of the neoprene rubber is 6.7, we can substitute these values into the formula:

C = (6.7 * 8.85 x 10⁻¹² F/m * 1.6 x 10-4 m²) / 0.012 x 10⁻³ m

After calculation, the capacitance is found to be approximately 9.31 x 10⁻¹² F.