Question

A projectile fired from a gun has initial horizontal and vertical components of velocity equal to 30 m/s and 40 m/s, respectively. What is the total initial velocity of the projectile?

1) 50 m/s
2) 60 m/s
3) 70 m/s
4) 80 m/s

Answer 1

The total initial velocity of a projectile can be found using the Pythagorean theorem by combining the horizontal and vertical components of velocity. In this case, the total initial velocity is 50 m/s.

Step-by-step explanation:

The total initial velocity of a projectile can be found by using the Pythagorean theorem. In this case, the horizontal and vertical components of velocity are given as 30 m/s and 40 m/s, respectively.

Using the Pythagorean theorem, we can find the total initial velocity:

vtotal = √(vhorizontal2 + vvertical2)

Plugging in the given values, we get:

vtotal = √((30 m/s)2 + (40 m/s)2) = √(900 m2/s2 + 1600 m2/s2) = √(2500 m2/s2) = 50 m/s

Therefore, the total initial velocity of the projectile is 50 m/s. Thus, the correct answer is option 1) 50 m/s.