Final answer:
The reaction between potassium t-butoxide and (1s, 2s)-1-bromo-2-methyl-1-phenylbutane likely yields a substitution product; the exact product depends on reaction conditions and would be confirmed through NMR spectroscopy.
Step-by-step explanation:
The product formed by the reaction of potassium t-butoxide with (1s, 2s)-1-bromo-2-methyl-1-phenylbutane is likely to be a substitution product where the bromide leaving group is replaced by the t-butoxide group. This type of reaction is a nucleophilic substitution, and since potassium t-butoxide is a strong base and the given substrate has steric hindrance, it may undergo an E2 elimination reaction as well. However, the exact product will depend on the specific reaction conditions such as solvent, temperature, and concentration. Performing these reactions in an academic setting typically involves analyzing the product using NMR spectroscopy and/or other forms of structural determination to confirm the chemical structure of the synthesized product.