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Evaluate the following limit, if it exists: lim x→1- g(x)

User CptScarlet
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Final answer:

To evaluate the limit lim x→1- g(x), plug in values of x less than 1 into the function and observe the trend of the output. In this case, as x approaches 1 from the left side, g(x) approaches -1.

Step-by-step explanation:

To evaluate the given limit lim x→1- g(x), we need to determine the behavior of the function g(x) as x approaches 1 from the left side. This means we consider values of x that are slightly less than 1. By plugging in values of x that are close to 1 but smaller than 1 into the function, we can observe the trend of the output. If the function approaches a specific value as x gets arbitrarily close to 1, then the limit exists and is equal to that value.

Let's consider an example. Suppose g(x) = x² - 1. Evaluating the function for x values less than 1, we have:

  1. When x = 0.9, g(0.9) = 0.9² - 1 = 0.81 - 1 = -0.19
  2. When x = 0.99, g(0.99) = 0.99² - 1 = 0.9801 - 1 = -0.0199
  3. When x = 0.999, g(0.999) = 0.999² - 1 = 0.998001 - 1 = -0.001999

From these values, we can see that as x approaches 1 from the left side, g(x) approaches -1. Therefore, the limit lim x→1- g(x) exists and is equal to -1.

User Ondrej Rafaj
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