Final answer:
The molar mass of Mn(ClO₂)₂ is calculated by summing the atomic masses of Mn, Cl, and O as they appear in the formula, resulting in a molar mass of 189.84 g/mol.
Step-by-step explanation:
The molar mass of Mn(ClO₂)₂ can be calculated by first determining the molar mass of each element in the compound and then multiplying by the number of atoms of each element present in the formula. Let's break it down:
- Manganese (Mn) has an atomic mass of approximately 54.94 g/mol.
- Chlorine (Cl) in ClO₂ has a mass of 35.45 g per mol, and since there are two Cl atoms, it totals 70.90 g.
- Oxygen (O) in ClO₂ has a mass of 16.00 g per mol. With two O's in each ClO₂ and two ClO₂ units in the formula, it totals 4 x 16.00 g = 64.00 g.
Adding these together:
- Mn: 54.94 g/mol
- 2x ClO₂: 2 x (35.45 g + 32.00 g) = 2 x 67.45 g = 134.90 g/mol
Then, the total molar mass of Mn(ClO₂)₂ is:
54.94 g/mol + 134.90 g/mol = 189.84 g/mol
Therefore, the molar mass of Mn(ClO₂)₂ is 189.84 g/mol.