Final answer:
The force between the two 1.7 kg masses with charges of 9.6 μC each and separated by 1.1 m is approximately 0.0678 N, as calculated using Coulomb's law. This value does not match any of the provided options suggesting a potential error in the question or options.
Step-by-step explanation:
The force between two 1.7 kg masses each carrying a charge of 9.6 μC and separated by 1.1 m can be calculated using Coulomb's law, which states that the force between two point charges (F) is directly proportional to the product of the charges (q1 and q2) and inversely proportional to the square of the distance (r) between them. The formula for Coulomb's law is F = k * |q1 * q2| / r^2, where k is Coulomb’s constant (k = 8.9875 × 10^9 N m^2/C^2).
Plugging the values into the formula:
F = (8.9875 × 10^9 N m^2/C^2) * |(9.6 × 10^-6 C) * (9.6 × 10^-6 C)| / (1.1 m)^2, we get:
F = (8.9875 × 10^9) * (9.216 × 10^-12) / 1.21, which simplifies to F ≈ 0.0678 N.
Thus, the magnitude of the force between the two masses is neither of the provided options (1) Cannot be determined, (2) 0 N, (3) 1.2 N, or (4) 2.4 N. It is approximately 0.0678 N, which is not one of the choices given. There could be an error in the problem statement or in the multiple-choice options.