Final answer:
The correct formula for iron(II) phosphate is Fe3(PO4)2 as this balances the charges of the iron(II) and phosphate ions by using three iron(II) ions and two phosphate ions.
Step-by-step explanation:
The correct formula for iron(II) phosphate is determined by balancing the charges of the iron(II) ions (Fe2+) and the phosphate ions (PO43-). Since neither charge is an exact multiple of the other, we need to find the least common multiple of the charges which is 6. To achieve a charge balance of 6+, we require three iron(II) ions, and for 6-, we need two phosphate ions. Consequently, the correct formula for iron(II) phosphate is Fe3(PO4)2.