Final answer:
To find dy/dx of 9y cos(x) = x² y², we use implicit differentiation and apply the product rule. Simplify the equation and isolate dy/dx, giving us (2x y² + 9y sin(x)) / (9 cos(x) - x² (2y)) as the derivative.
Step-by-step explanation:
To find the derivative dy/dx of the equation 9y cos(x) = x² y², we need to use implicit differentiation because y is a function of x and it is not isolated on one side of the equation. Here's a step-by-step process:
- Differentiate both sides of the equation with respect to x.
- Apply the product rule to y cos(x) which becomes y' cos(x) - y sin(x), where y' represents dy/dx.
- Simplify the equation and solve for dy/dx.
Let's differentiate both sides:
9y' cos(x) - 9y sin(x) = 2x y² + x² (2y)y'
Rearrange terms to isolate y' on one side:
y' (9 cos(x) - x² (2y)) = 2x y² + 9y sin(x)
Solve for y':
y' = (2x y² + 9y sin(x)) / (9 cos(x) - x² (2y))
The derivative dy/dx for the given equation is therefore (2x y² + 9y sin(x)) / (9 cos(x) - x² (2y)).