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What is the amount of work (in j) that an external agent must do to stretch the spring 8.90 cm from its unstretched position?

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Final answer:

To find the amount of work done to stretch the spring, we need to use Hooke's Law and the equation W = (1/2)kx^2, where W is the work done, k is the force constant of the spring, and x is the displacement of the spring. Given that the spring stretches 8.90 cm from its unstretched position, we can calculate the work done using the formula W = (1/2)kx^2.

Step-by-step explanation:

In order to find the amount of work done to stretch the spring, we need to use Hooke's Law, which states that the force exerted by a spring is directly proportional to its displacement from its equilibrium position.

Therefore, the equation for the force exerted by the spring is given by F = -kx, where F is the force, k is the force constant of the spring, and x is the displacement of the spring.

To find the amount of work done, we can use the equation W = (1/2)kx^2, where W is the work done, k is the force constant of the spring, and x is the displacement of the spring.

Given that the spring stretches 8.90 cm from its unstretched position, we can calculate the work done as follows:

W = (1/2)kx^2 = (1/2)(FORCE_CONSTANT)(DISPLACEMENT^2) = (1/2)(FORCE_CONSTANT)(0.089 m)^2 = (1/2)(FORCE_CONSTANT)(0.007921 m^2)

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