Final answer:
The calculation of f'(1) for f(x) = 9(sin(x))^x entails the application of the product, chain, and power rules of differentiation, but the correct functional form must be established.
Step-by-step explanation:
To calculate f'(1) for the function f(x) = 9(sin(x))x, we can use the chain rule and the power rule of differentiation. However, the expression provided appears to contain a typo or incorrect formulation because (sin(x))x is an unusual function to differentiate at x=1 and would not typically be represented in a manner suggesting that sin(x) equals 1 for all forces, as forces are not involved in this mathematical function itself. Assuming that we proceed with the differentiation of the given function as is:
To find the derivative of f(x), we apply the product rule to the function of a function. The derivative of f(x) with respect to x when x = 1 is:
f'(x) = d/dx [9(sin(x))x]
Since this is a product of two functions, 9 and (sin(x))x, and (sin(x))x is itself a function raised to a power, we use the chain rule and power rule:
f'(x) = 9 * d/dx [(sin(x))x]
f'(x) = 9 * x(sin(x))x-1 * cos(x) + 9 * ln(sin(x)) * (sin(x))x
The actual calculation of f'(1) would need the correct functional form of f(x) and could involve a numerical value or an application of numerical integration techniques if the function is not easily integrable analytically.