Final answer:
To determine the height at which the rock was released, we can use the equations of motion. Given the rock's initial velocity of 6.000 m/s and the time it takes to fall to the ground (1.443 s), we can solve for the height using the equation h = v0 * t - (1/2) * g * t^2. Plugging in the values, we find that the rock was released from a height of 5.245 meters.
Step-by-step explanation:
To calculate the height at which the rock was released, we can use the equations of motion. Since the rock is thrown straight upward, its initial vertical velocity is 6.000 m/s and it takes 1.443 s to fall back to the ground. The equation we can use is:
h = v0 * t - (1/2) * g * t^2
Where:
h is the height
v0 is the initial velocity (6.000 m/s)
t is the time (1.443 s)
g is the acceleration due to gravity (9.8 m/s^2)
Plugging in the values, we get:
h = (6.000 m/s) * (1.443 s) - (1/2) * (9.8 m/s^2) * (1.443 s)^2
Solving the equation gives us the height h = 5.245 m. Therefore, the rock was released from a height of 5.245 meters.