Final answer:
The force between two protons released from rest when they are 0.750 nm apart can be calculated using Coulomb's Law. Plugging the given values into the formula, the force is approximately 3.413 x 10^-7 N.
Step-by-step explanation:
According to Coulomb's Law, the force between two point charges can be calculated using the formula F = (k * q1 * q2) / r^2, where F is the force, k is the electrostatic constant (9.0 x 10^9 N m^2/C^2), q1 and q2 are the charges, and r is the distance between the charges.
In this case, the charges are both protons, which have a charge of +1.6 x 10^-19 C. The distance between them is 0.750 nm, which is equivalent to 7.50 x 10^-10 m. Plugging these values into the formula:
F = (9.0 x 10^9 N m^2/C^2) * (+1.6 x 10^-19 C) * (+1.6 x 10^-19 C) / (7.50 x 10^-10 m)^2
F = 3.413 x 10^-7 N
Therefore, the force between the two protons is approximately 3.413 x 10^-7 N.