Final answer:
The theoretical yield of water in grams when 85 ml of 2.5 M Ca(OH)2 is reacted is 7.65 grams.
Step-by-step explanation:
To find the theoretical yield of water in grams when 85 ml of 2.5 M Ca(OH)2 is reacted, we need to use the balanced chemical equation and determine the stoichiometry of the reaction.
The balanced chemical equation is: Ca(OH)2 + 2HCl → CaCl2 + 2H2O.
From the equation, we can see that one mole of Ca(OH)2 reacts with two moles of HCl to produce two moles of water.
- Convert the volume of Ca(OH)2 solution to moles: 85 ml * (1 L/1000 ml) * (2.5 mol/L) = 0.2125 mol.
- Using the stoichiometry of the reaction, we can see that 1 mole of Ca(OH)2 produces 2 moles of water. Therefore, 0.2125 mol of Ca(OH)2 would produce 0.425 mol of water.
- Convert the moles of water to grams: 0.425 mol * (18.015 g/mol) = 7.65 grams.
Therefore, the theoretical yield of water in grams when 85 ml of 2.5 M Ca(OH)2 is reacted is 7.65 grams.