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Find an equation of the tangent plane to the given surface at the specified point. z = 5(x - 1)² + 5(y - 3)² - 4, (2, -1, 29)

User Rebz
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Final answer:

To find the equation of the tangent plane to the given surface at the specified point, we can use the formula z - z₁ = fₓ(x - x₁) + fᵧ(y - y₁), where (x₁, y₁, z₁) is the specified point and fₓ and fᵧ are the partial derivatives of the surface equation with respect to x and y. Substitute the values into the formula and simplify to get the equation of the tangent plane as 10x - 40y + z = -39.

Step-by-step explanation:

To find the equation of the tangent plane to the surface, we can use the formula:

z - z₁ = fₓ(x - x₁) + fᵧ(y - y₁)

where (x₁, y₁, z₁) is the specified point and fₓ and fᵧ are the partial derivatives of the surface equation with respect to x and y.

For the given surface, z = 5(x - 1)² + 5(y - 3)² - 4, and the specified point is (2, -1, 29). We can start by finding fₓ and fᵧ:

fₓ = 10(x - 1)
fᵧ = 10(y - 3)

Now substitute the values into the formula to get the equation of the tangent plane:

z - 29 = 10(2 - 1)(x - 2) + 10(-1 - 3)(y - (-1))

Simplifying further:

z - 29 = 10(x - 2) - 40(y + 1)

Finally, rearrange the equation to get the standard form:

10x - 40y + z = -39

User Geat
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