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The reaction below has a Kc value of 1.0 × 10¹². What is the value of Kp for this reaction at 200 K? 2 SO₂(g) + O₂(g) ⇌ 2 SO₃(g)

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Final answer:

The Kp value for the given reaction at 200K, when Kc is 1.0 × 10¹², can be calculated using the formula Kp = Kc(RT)Δn, where Δn is the change in moles of gaseous reactants and products.

Step-by-step explanation:

The value of Kp for the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g) at 200K, given Kc is 1.0 × 1012, can be calculated using the relationship between Kp and Kc which involves the gas constant (R) and the temperature (T). The formula to convert Kc to Kp is Kp = Kc(RT)Δn, where Δn is the change in moles of gas. For this reaction, Δn = (moles of SO3) - (moles of SO2 + moles of O2) = 2 - (2 + 1) = -1. Using R = 0.08206 L atm/mol·K, and plugging in the values, the calculation yields Kp = Kc(RT)Δn = 1.0 × 1012 × (0.08206 L atm/mol·K × 200K)-1, which can be solved to find the value of Kp at 200 K.

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