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In ΔMNO, m = 570 cm, n = 350 cm and o=230 cm. Find the measure of ∠O to the nearest 10th of a degree.

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n ΔMNO with sides 570cm, 350cm, and 230cm, ∠O is approximately 34.96°. This was calculated using the Law of Cosines.

Solving for ∠O in ΔMNO

Given:

ΔMNO with side lengths:

m = 570 cm

n = 350 cm

o = 230 cm

To find:

Measure of ∠O (rounded to the nearest 10th of a degree)

Using the Law of Cosines:

The Law of Cosines states that for any triangle ΔABC with sides a, b, and c, and angle C opposite side c:

c² = a² + b² - 2ab * cos(C)

In our case, we want to find ∠O (opposite side o), so we can rewrite the formula as:

o² = m² + n² - 2mn * cos(∠O)

Substituting known values:

230² = 570² + 350² - 2(570)(350) * cos(∠O)

Solving for cos(∠O):

cos(∠O) = (570² + 350² - 230²) / (2 * 570 * 350)

cos(∠O) ≈ 0.8276

Finding ∠O:

∠O ≈ cos⁻¹(0.8276)

∠O ≈ 34.96° (rounded to the nearest 10th of a degree)

Therefore, the measure of ∠O in ΔMNO is approximately 34.96 degrees.