Question

Consider the first six terms of this sequence: 2, 5, 8, 11, 14, 17,........What would be the 41st term of this sequence?

A. 125
B. 122
C. 2431533
D. 43

Answer 1

122

Explanation:

The nth term for this sequence is 3n - 1.

3 x 41 = 123

123 - 1 = 122