Question

For the body-centered cubic crystal structure, how are the unit cell edge length a and the atomic radius r related?

Answer 1

In a body-centered cubic (BCC) crystal structure, the unit cell edge length 'a' and the atomic radius 'r' are related by a = 4r/(√3).

Step-by-step explanation:

In a body-centered cubic (BCC) crystal structure, the unit cell edge length 'a' and the atomic radius 'r' are related as follows:

a = 4r/(√3)

For a BCC structure, the body diagonal of the cube is equal to four atomic radii, so we can use the Pythagorean theorem to solve for 'a' in terms of 'r'.

For example, if the atomic radius 'r' is given, plug in the value into the equation to find the unit cell edge length 'a'.