Final answer:
The average force exerted on blood that's being accelerated from 0.20 m/s to 0.33 m/s over a 0.12 s period is approximately 0.022 N. This was calculated using Newton's second law (F=ma) after determining the acceleration from the change in velocity and the time interval.
Step-by-step explanation:
The question involves calculating the average force exerted on blood during an acceleration, which is a concept from Physics. This can be done using Newton's second law of motion, which states that force is equal to mass times acceleration (F=ma).
First, we need to calculate the acceleration (a) of the blood using the formula for acceleration, which is the change in velocity (final velocity - initial velocity) divided by the time interval during which the change occurred. The change in velocity (Δv) is 0.33 m/s - 0.20 m/s = 0.13 m/s. The time interval (Δt) is 0.12 s.
Now let's calculate the acceleration:
a = Δv / Δt
a = 0.13 m/s / 0.12 s
a = 1.083 m/s2
Now we use the mass (m) of the blood which is 20 g, or 0.02 kg (since 1 g = 0.001 kg), and the acceleration to calculate the force:
F = ma
F = 0.02 kg × 1.083 m/s2
F = 0.02166 N
This rounds to approximately 0.022 N, which is not among the options provided in the question. The closest answer to our calculation from the options given is 0.02 N, but since this value is not on the list, it's possible there may be a mistake or oversight in the question or the options provided.