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What is the mole fraction of I₂ in a solution made by dissolving 27.8 g of I₂ in 245 g of hexane, C₆H₁₄?

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Final answer:

To find the mole fraction of iodine (I2) in the solution, divide the moles of iodine, calculated by its mass divided by molar mass, by the total moles of iodine and hexane. The mole fraction of I2 is approximately 0.0371.

Step-by-step explanation:

Calculating Mole Fraction of Iodine in a Solution

To calculate the mole fraction of iodine (I2) in a solution made by dissolving 27.8 g of I2 in 245 g of hexane (C6H14), we first need to determine the number of moles of each component. The molar mass of I2 is approximately 253.8 g/mol. We calculate the moles of iodine by dividing the mass of the dissolved iodine by its molar mass.

Moles of I2 = 27.8 g / 253.8 g/mol = 0.1095 mol

We then calculate the number of moles of hexane using its molar mass, which is approximately 86.17 g/mol.

Moles of hexane (C6H14) = 245 g / 86.17 g/mol = 2.8425 mol

Now, the mole fraction of I2 is calculated by dividing the moles of I2 by the sum of the moles of I2 and hexane:

Mole fraction of I2 = Moles of I2 / (Moles of I2 + Moles of hexane) = 0.1095 mol / (0.1095 mol + 2.8425 mol)

Mole fraction of I2 = 0.1095 mol / 2.9520 mol ≈ 0.0371

The mole fraction of I2 in the solution is therefore approximately 0.0371.

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