Final answer:
The acceleration of the block sliding down the inclined plane is approximately 6.26 m/s².
Step-by-step explanation:
The acceleration of the block sliding down the inclined plane can be calculated using the following formula:
acceleration = (g * sin(theta)) - (friction / mass)
- g is the acceleration due to gravity (9.8 m/s²)
- theta is the angle of the inclined plane (45°)
- friction is the force of friction opposing the motion (45 N)
- mass is the mass of the block (3 kg)
Plugging in the values, we get:
acceleration = (9.8 * sin(45°)) - (45 / 3)
Simplifying the equation, we find that the acceleration of the block is approximately 6.26 m/s².