The force constant of the spring in the system is 9800 N/m
The force constant of a spring can be determined using Hooke's law, which states that the force exerted by a spring is directly proportional to its displacement from the equilibrium position. In this case, the spring stretches 8.00 cm for a 10.0 kg load. To find the force constant, we can rearrange Hooke's law equation F = kx, where F is the force, k is the force constant, and x is the displacement. Substituting the given values, we have:
F = kx
784 N = k * 0.08 m
Simplifying the equation, we get:
k = 784 N / 0.08 m
= 9800 N/m
The probable question may be:
What is the force constant of a spring if it stretches 8.00 cm for a 10.0 kg load, according to Hooke's law?