Final Answer:
The tension in each rope supporting the 1000 kg steel beam is approximately 9810 N.
Explanation:
The tension in the ropes can be determined by considering the forces acting on the beam. With the gravitational force pulling the beam downward and the beam in equilibrium, the tension in each rope equals the force required to counterbalance the weight of the beam.
The gravitational force acting on the beam can be calculated using the formula F = m * g, where 'm' is the mass of the beam and 'g' is the gravitational acceleration. Substituting the given values (m = 1000 kg, g ≈ 9.81 m/s²) gives the gravitational force as 9810 N.
Each rope supports half of the weight of the beam, so the tension in each rope is also 9810 N to counterbalance the gravitational force pulling the beam downward.
Here's the completion question
A 1000 kg steel beam is supported by the two ropes shown in (Figure 1). Calculate the tension in the ropes supporting the beam.
- Mass of the steel beam = 1000 kg
- Gravitational acceleration ≈ 9.81 m/s²
Calculate the tension in the ropes supporting the steel beam. Assume the beam is in equilibrium and neglect any other external forces acting on the system.