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The reaction below has a Kp value of 41. What is the value of Kc for this reaction at 400 K?

N₂(g) + 3 H₂(g) ⇌ 2 NH₃(g)

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Final answer:

To convert the value of Kp (41) to Kc for the given reaction at 400 K, the equation Kp = Kc(RT)^Δn is used, where R is the gas constant, T is the temperature in Kelvin, and Δn is the change in the number of moles of gas. For this reaction, Δn is -2.

Step-by-step explanation:

The student has asked about converting the value of Kp to Kc for the reaction N₂(g) + 3 H₂(g) ⇌ 2 NH₃(g) at 400 K. The Kp value given is 41.

To convert Kp to Kc, we use the equation:

Kp = Kc(RT)^Δn

Where:

  • R is the gas constant (0.0821 L·atm/K·mol)
  • T is the temperature in Kelvin
  • Δn is the change in the number of moles of gas

In this reaction, Δn = (2 - (1 + 3)) = -2 because 2 moles of NH₃ gas are produced from 1 mole of N₂ and 3 moles of H₂ gas.

Therefore, solving for Kc we get:

Kc = Kp / (RT)^Δn

Inserting the values (with T = 400 K and Δn = -2):

Kc = 41 / (0.0821 * 400)^-2

When you compute this, you'll find the value of Kc.

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