Question

How much work does the force vector f do when the proton moves along the straight-line path from the point (0.10m,0) to the point (0.10m,0.40m)?

Answer 1

The work done by the force vector f is 0 J.

Step-by-step explanation:

The work done by a force can be calculated using the formula:

Work = Force * Distance * cos(angle)

In this case, the force vector f = (3 N)î + (4 N)Ĵĵ and the proton moves from the point (0.10 m, 0) to (0.10 m, 0.40 m).

The distance is the difference in y-coordinates, which is 0.40 m - 0 m = 0.40 m.

The angle between the force vector and the displacement vector is 90 degrees, so cos(angle) = cos(90) = 0.

Therefore, the work done by the force vector f is:

Work = (3 N) * 0.40 m * 0 = 0 J