Final answer:
The major and minor products of the reaction between Br and NaOEt are sodium bromide (NaBr) and ethyl bromide (C2H5Br).
Step-by-step explanation:
The major and minor products of the reaction between Br and NaOEt are sodium bromide (NaBr) and ethyl bromide (C2H5Br). The reaction can be represented by the following equation:
Br + NaOEt → NaBr + C2H5Br
The major product, NaBr, is formed by the replacement of the ethoxide ion (OEt-) by the bromide ion (Br-). The minor product, C2H5Br, is formed by the replacement of the bromine atom (Br) in Br by the ethyl group (C2H5).