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Nitrogen gas and hydrogen gas react to form ammonia gas. Suppose you have 2 moles of nitrogen gas and 3 moles of hydrogen gas in a reactor. What is the balanced chemical equation for this reaction?

1) 2NH₃(g) = N₂(g) + 3H₂(g)
2) N₂(g) + 3H₂(g) = 2NH₃(g)
3) 2NH₃(g) = N₂(g) + 2H₂(g)
4) N₂(g) + 2H₂(g) = 2NH₃(g)

User Jerami
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1 Answer

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Final answer:

The balanced chemical equation for the reaction between nitrogen gas and hydrogen gas to form ammonia gas is N₂(g) + 3H₂(g) = 2NH₃(g). so, option 2 is the correct answer.

Step-by-step explanation:

The balanced chemical equation for the reaction between nitrogen gas (N₂) and hydrogen gas (H₂) to form ammonia gas (NH₃) is: N₂(g) + 3H₂(g) = 2NH₃(g).

The coefficients in the balanced equation represent the mole ratio of each substance. In this case, 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃.

This reaction is known as the Haber process and is used industrially to produce ammonia. The equilibrium constant of this reaction varies with temperature.

The balanced chemical equation for the reaction of nitrogen gas and hydrogen gas to form ammonia gas is N₂(g) + 3H₂(g) ⇒ 2NH₃(g). When you have 2 moles of nitrogen gas and 3 moles of hydrogen gas in a reactor, you can see from the balanced equation that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia. Therefore, with the provided amounts, only 2 moles of hydrogen can be used up with 2/3 mole of nitrogen to form 4/3 moles of ammonia, since hydrogen is the limiting reactant. The correct option from the given choices is option 2) N₂(g) + 3H₂(g) = 2NH₃(g).

User Tim Biegeleisen
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