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Determine the volume change, in ft3, when 1 lb of water, initially saturated liquid, is heated to saturated vapor while pressure remains constant at 1.0, 14.7, 100, and 500 lbf/in.2?

User Dawidg
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Final Answer:

The volume change when 1 lb of water is heated from saturated liquid to saturated vapor at constant pressure varies with the pressure conditions. The volume changes are approximately 4.42 ft³ at 1.0 lbf/in², 6.59 ft³ at 14.7 lbf/in², 8.61 ft³ at 100 lbf/in², and 10.19 ft³ at 500 lbf/in².

Step-by-step explanation:

When water undergoes a phase change from saturated liquid to saturated vapor, its specific volume changes based on pressure conditions. The specific volume at each pressure is determined by consulting steam tables or Mollier charts for water. The volume change is calculated by subtracting the initial specific volume of saturated liquid from the final specific volume of saturated vapor.

For instance, at 1.0 lbf/in², the specific volume of saturated liquid is approximately 0.016 ft³/lb, and the specific volume of saturated vapor is approximately 4.48 ft³/lb. The volume change is calculated as 4.48 ft³/lb - 0.016 ft³/lb ≈ 4.42 ft³.

This process is repeated for each pressure condition, resulting in volume changes of approximately 6.59 ft³, 8.61 ft³, and 10.19 ft³ at 14.7 lbf/in², 100 lbf/in², and 500 lbf/in², respectively. These values provide insights into the expansion of water during phase change under different pressure conditions.

User Kallen
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