Final answer:
The power dissipated in the 30 Ω resistor can be calculated using Joule's law. Assuming a current of 2 A flowing through the resistor, the power is found to be 120 W.
Step-by-step explanation:
The power dissipated in the 30 Ω resistor can be calculated using Joule's law. The power in watts (W) can be found by using the equation P = IV, where P is the power, I is the current, and V is the voltage. In this case, since the voltage is not given, we need to use Ohm's law to find it. Ohm's law states that V = IR, where R is the resistance and I is the current. Therefore, we can find V by multiplying the current flowing through the 30 Ω resistor by 30 Ω. Once we have the voltage, we can substitute it into the power equation along with the current flowing through the resistor.
Let's assume the current flowing through the 30 Ω resistor is 2 A. Using Ohm's law, V = IR = (2 A)(30 Ω) = 60 V. Now substituting the values of V and I into the power equation, P = IV = (2 A)(60 V) = 120 W. Therefore, the power dissipated in the 30 Ω resistor is 120 W.