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A golf ball is selected at random from a golf bag. If the golf bag contains _______?

User Rsacc
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1 Answer

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The probability of selecting a green or black golf ball from the golf bag is
( (13)/(15) )or approximately 0.867.

The probability of selecting a green or black golf ball from the golf bag can be calculated by adding the individual probabilities of selecting a green ball and a black ball.

The total number of green balls is 7, and the total number of black balls is 6. The total number of balls in the bag is 7 (green) + 6 (black) + 2 (orange) = 15.

Therefore, the probability of selecting a green ball is
( (7)/(15) ) and the probability of selecting a black ball is
( (6)/(15) ).

The probability of selecting a green or black ball is the sum of these two probabilities, which is:


[ P(\text{green or black}) = P(\text{green}) + P(\text{black}) = (7)/(15) + (6)/(15) = (13)/(15) ]

So, the probability of selecting a green or black golf ball from the golf bag is
( (13)/(15) )or approximately 0.867.

Complete question:

A golf ball is selected at random from a golf bag. If the golf bag contains 7 green balls, 6 black balls, and 2 orange balls, find the probability of the following event. The probability that the golf ball is green or black?

User Teodor Anton
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