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Find a unit vector that is parallel to the line tangent to the parabola y = x² at the point (6, 36).

User Parixit
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1 Answer

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Final answer:

The unit vector parallel to the tangent line of the parabola y = x² at the point (6, 36) can be found by finding the slope of the tangent line.

Step-by-step explanation:

Unit Vector Parallel to Tangent Line of Parabola

To find a unit vector that is parallel to the line tangent to the parabola y = x² at the point (6, 36), we need to find the slope of the tangent line at that point.

The derivative of y = x² is dy/dx = 2x. Substituting x = 6 into the derivative equation, we get dy/dx = 2*6 = 12.

Therefore, the slope of the tangent line at the point (6, 36) is 12. Now, we can find the unit vector with this slope as its direction.

User Vmr
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