Question

1. (2ab^5)^4/ab^3
2. (x^3y^5/ab^7)^2
3. 5mn^7-1​

Answer 1

`\rm{1.)16a {}^(3)b {}^(17) }`

= (2ab^5)^4

= 2ab^5×2ab^5×2ab^5×2ab^5

= 16a^4b^9

= 16a^4b^9/ab^3

= 16a^3b^17

`\rm2.) \frac{x {}^(6) y {}^(10) }{a {}^(2)b {}^(14) }`

= (x^3y^5)^2

= (x^6y^10)

= (ab^7)^2

= (ab^14)

= (x^6y^10)/ab^14

`\rm3.)4mn {}^(7)`

= 5mn^7 - 1

= 4mn^7