Question

: A line passes through the point (-6, 10) with a slope of 7/2

Answer 1

Answer: 7x-2y+62=0

steps

1. y-y1=m(x-x1)
2. where y1=10,x1=-6 and m=7/2
3. y-10=7/2(x-(-6))
4. 2(y-10=7x/2+21)
5. 2y-20=7x+42
6. 7x-2y+62=0