237,233 views
19 votes
19 votes
4. The original function is f(x) = x². Circle the type of reflection that has occurred (x-axis, y-axis or neither). a. g(x) = -x² b. h(x) = 2/1/2x² c. k(x) = (-x)² x-axis x-axis x-axis y-axis y-axis y-axis neither neither neither ​

4. The original function is f(x) = x². Circle the type of reflection that has occurred-example-1
User Salgiza
by
2.8k points

1 Answer

15 votes
15 votes

Explanation:

a. g(x) = -x² x-axis

what was originally above the x-axis (positive function values), is now below (negative function values). and vice versa.

b. h(x) = 1/2 x² neither

this does not flip things around. it only "squeezes" the curve down a little bit.

c. k(x) = (-x)² y-axis

although we would not notice. this turns negative x-values to positive ones, and positive x- values into negative ones. so, the left side of the curve trades place with the right side.

but because the left side of the original function is already the mirror image of the right side, we don't see a difference in the graph when mirroring the sides. but we did reflect across the y-axis.

User Lakeishia
by
2.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.