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Evaluate 5 y' – yº if y = – 8.​

User Rakex
by
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1 Answer

1 vote

The value of
\(5y' - y^\circ\)when
\(y = -8\) is \(8^\circ\).

To evaluate
\(5y' - y^\circ\) when \(y = -8\), we need to substitute the value of y into the expression.

Given that
\(y = -8\), let's find y' (the derivative of y with respect to some variable, typically x and
\(y^\circ\) (the angle measure in degrees).

Without the specific form of the function \(y\) with respect to \(x\) and its derivative, we cannot determine \(y'\) directly. However, assuming \(y\) is a constant with respect to
\(x\), \(y' = 0\).

Now, substitute the values into the expression:


\[5y' - y^\circ = 5(0) - (-8)^\circ\]\[= 0 + 8^\circ\]

So, the value of
\(5y' - y^\circ\)when
\(y = -8\) is \(8^\circ\).

User Sjdenny
by
8.3k points