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1-methyl-1,3-cyclohexadiene with 2-butyne and with NBS in CCl4 provide the drawn out mechanism for both please.

User Chace
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Final answer:

The mechanism for the reaction of 1-methyl-1,3-cyclohexadiene with 2-butyne and NBS in
CCl_4involves a Diels-Alder reaction and radical bromination.

Step-by-step explanation:

The mechanism for the reaction of 1-methyl-1,3-cyclohexadiene with 2-butyne and NBS in
CCl_4can be described as follows:

1. In the presence of
CCl_4, 1-methyl-1,3-cyclohexadiene reacts with 2-butyne through a Diels-Alder reaction. The conjugated diene and the alkene form a cyclic six-membered transition state to produce a six-membered cyclic product.

2. The reaction between 1-methyl-1,3-cyclohexadiene and NBS proceeds through a radical bromination mechanism. NBS (N-bromosuccinimide) is a source of bromine radicals, which react with the cyclohexadiene to form brominated products.

User ACRL
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