Final answer:
Mrs. Serrano walked a total distance of 22 meters.
Step-by-step explanation:
To find the total distance Mrs. Serrano walked, we add up the distances she walked to Joe's desk and to Steven's desk, and then the diagonal distance back to the front of the class.
First, Mrs. Serrano walks 3.2 meters to Joe's desk.
Then, she walks 8.3 meters to Steven's desk.
Finally, she walks diagonally back to the front of the class, which we can approximate as a distance of 11.5 meters using the Pythagorean theorem.
Adding up all the distances, the total distance Mrs. Serrano walked is
3.2 + 8.3 + 11.5
= 22 meters.