Final answer:
The activation of adenylate cyclase in the liver leads to the release of glucose in response to the overdose of glipizide.
Step-by-step explanation:
The activation of which one of the following liver enzymes leads to the release of glucose by the liver in response to the overdose of glipizide?
- Adenylate cyclase
- Protein kinase A
- Glycogen synthase
- Phosphorylase kinase
- Glycogen phosphorylase
The correct answer is (A) Adenylate cyclase. When the blood glucose level falls, hormones like glucagon and epinephrine are released, which bind to hormone receptors on the cell membrane and activate adenylate cyclase. This enzyme converts ATP to cyclic AMP (CAMP), leading to the activation of protein kinase A (PKA) and phosphorylation of enzymes involved in glycogenolysis, including glycogen phosphorylase, which catalyzes the breakdown of glycogen into glucose.