Question

A 600 kg cannon is used to fire a 15kg cannonball to the right at a velocity of 500 m/s.

What is the cannonball’s final momentum in kg*m/s?

Answer 1

Since there is no external force overall momentum of the system is constant which is zero.

⇒Mv 1+mv 2 =0

⇒600(v 1 )+15(500)=0

⇒v1≈7500 -- 600

⇒v 1 =−6900m/s

So, cannon will recoil at the speed of 6900m/s

Step-by-step explanation:

v2 = - 2 m/s

From the above condition, the negative sign demonstrates that the speed of the weapon is inverse to the speed of the projectile. it implies the weapon will pull back

Last speed (v) of an item rises to starting speed (u) of that article in addition to speed increase (a) of the item times the passed time (t) from u to v.

Speed (v) is a vector amount that actions uprooting (or change ready, Δs) over the adjustment of time (Δt), addressed by the situation v = Δs/Δt.