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31 votes
31 votes
If 1. 23 g of chlorine gas dissolves in

0. 95 L of water at 15. 6 psi, at what

pressure (in psi) would you be able

to dissolve 1. 89 g in the same

amount of water?

User Egghese
by
2.7k points

1 Answer

13 votes
13 votes

Answer:

Step-by-step explanation:

this is one of the PV=nrt formula questions

are you familiar with that formula from the gas law??

where P = pressure,

V = volume

n = the number of moles

r = is some constant, look that one up

t is the temperature, often a Standard temp is used of 20 C

so you'll have to figure out the molar amount of 1.23 g of chlorine. for n

put that amount of moles of the gas.

V is the volume, 0.95 L

P is the 15.6 psi

then equate the equations

(15.6*.95 ) / [moles of chorine gas in 1.23 g * r * 20 (b/c of STP)] =(P*.95) / [n molar amount of 1.89 g of chlorine gas * r * 20 ( STP, again)]

r is that constant like 8.84x10-9 or something, look it up

Now you only have "P" left on the right hand side of the equation

I'll algebra the equation down for you some.

14.82 / [n(1.23) *r*20] = P * (.95/[n(1.89)*r*20]

you'll be able to solve this pretty easily once you plug in the molar values, and the constant value for "r" :)

got it?

User Gerald T
by
3.1k points