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3 votes
Analyze the following code:

public class Test implements Runnable {

public static void main(String[] args) {
Test t = new Test();
}

public Test() {
Thread t = new Thread(this);
();
}

public void run() {
System.out.println("test");
}
}

A.) The program has a compilation error because t is defined in both the main() method and the constructor Test().

B.) The program compiles fine, but it does not run because you cannot use the keyword in the constructor.

C.) The program compiles, runs, and displays nothing.

D.) The program compiles, runs, and displays test.

User Rbar
by
8.4k points

1 Answer

5 votes

Final answer:

The program compiles, runs, and displays 'test'.

Step-by-step explanation:

The correct option is D.) The program compiles, runs, and displays 'test'.

The code creates a class named 'Test' that implements the 'Runnable' interface. It contains a main() method which creates an instance of the 'Test' class. In the constructor of 'Test', a new thread is created and started with the 'run()' method as its target. The 'run()' method simply prints out the word 'test'.

So, when the program is executed, it will compile without any errors, run the main() method, create a new instance of 'Test', start a new thread, and display the word 'test' as the output.

User Felix Runye
by
8.2k points