Question

Code Analysis (1)

Below is a faulty program. It includes a test case that results in failure. Answer the following questions A - D about this program:

public int countPositive(int[] x) {
//Effects: If x == null throw NullPointerException
//Else return the number of positive (non-zero) elements in x
int count = 0;
for (int i = 0; i < ; i++) {
if (x[i] >= 0) {
count++;
}
}
return count;
}
// Test Input: x = [-4, 2, 0, 2]
// Expected output = 2

Identify the fault in this program:

A.) For loop is incorrect: it is iterating from low to high

B.) Initialization of count variable is incorrect

C.) If conditional is incorrect: it should consider values less than 0 as well

D.) If conditional is incorrect: it is testing for 0 as well

Answer 1

The fault in this program is in the if conditional, as it doesn't count zero as a positive element.

Step-by-step explanation:

The fault in this program can be identified in option D. The if conditional is incorrect because it is testing for 0 as well. In the given code, the condition x[i] >= 0 only counts the positive elements in the array, excluding the negative elements. However, the test case expects the count to include zero as well, which is considered non-zero in this program.

To fix this fault, change the condition to x[i] > 0. This will include all elements greater than zero in the count, satisfying the expected output of the test case.