Question

Place the following compounds in order of increasing boiling point.

-LiBr
-Cl2
-CH3OH

Answer 1

The compounds Cl2, CH3OH, and LiBr, when arranged in order of increasing boiling point, are in the sequence of Cl2 with the lowest, then CH3OH, and finally LiBr with the highest boiling point.

Step-by-step explanation:

To place the compounds LiBr, Cl2, and CH3OH in order of increasing boiling point, we must consider the types of intermolecular forces each compound exhibits.

• Chlorine (Cl2) is a diatomic molecule with relatively weak London dispersion forces, due to its low molar mass.
• Lithium bromide (LiBr) is an ionic compound, which means it has strong ionic bonds that require more energy to overcome.
• Methanol (CH3OH) is a polar molecule with hydrogen bonding, which has a significant effect on boiling point.

Therefore, when arranged from lowest to highest boiling point, the order is Cl2 (−34.6°C) < CH3OH (64.7°C) < LiBr (1,382°C).