Question

The reaction X → products is second order in X and has a rate constant of 0.035 M^−1 s^−1. If a reaction mixture is initially 0.80 M in X, what is the concentration of X after 120. seconds?

Answer 1

The concentration of X after 120 seconds is approximately 0.560 M.

Step-by-step explanation:

The reaction X → products is second order in X and has a rate constant of 0.035 M-1 s-1. To find the concentration of X after 120 seconds, we can use the second-order rate equation:

1/[X] - 1/[X]₀ = kt

Where [X] is the concentration of X at time t, [X]₀ is the initial concentration of X, k is the rate constant, and t is time.

Plugging in the values:

1/[X] - 1/0.80 = (0.035)(120)

Simplifying the equation:

1/[X] = 0.035(120) + 1/0.80

Calculating the concentration of X:

[X] = 1 / (0.035(120) + 1/0.80)

[X] ≈ 0.560 M