Final answer:
The slope of Mr. Strayger's zipline is approximately 0.0026, determined by dividing the vertical change of 528 feet by the horizontal length of 200,640 feet.
Step-by-step explanation:
To find the slope of Mr. Strayger's zipline, we use the slope formula, which is the change in vertical distance divided by the change in horizontal distance.
The zipline descends from 1,144 feet to 616 feet, a change of 1,144 - 616 = 528 feet.
As it is 200,640 feet long horizontally, the slope would be 528 feet vertical over 200,640 feet horizontal.
Therefore, the slope (m) is:
m = vertical change / horizontal change
m = 528 ft / 200,640 ft
m = 0.002631578947368421
The slope is approximately 0.0026, with the understanding that this is a very gentle slope considering the long horizontal distance of the zipline.