Question

A straight wire carries a current of 10 A at an angle of 30 degrees with respect to the direction of a uniform 0.30-T magnetic field. Find the magnitude of the magnetic force on a 0.50-m length of the wire.

A. 0.75 N
B. 6.0 N
C. 3.0 N
D. 1.5 N

Answer 1

The magnitude of the magnetic force on a 0.50-m length of wire carrying a current of 10 A at an angle of 30 degrees to a 0.30-T magnetic field is 0.75 N.

Step-by-step explanation:

The magnetic force on a current-carrying wire can be calculated using the formula F = BILsinθ, where F is the force, B is the magnetic field, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field. In this case, the current is 10 A, the length of the wire is 0.50 m, and the angle between the wire and the magnetic field is 30 degrees. The formula becomes:

F = (0.30 T)(10 A)(0.50 m)sin(30°)

F = (0.30)(10)(0.50)(0.5)

F = 0.75 N

Therefore, the magnitude of the magnetic force on the 0.50 m length of wire is 0.75 N.