Question

A 10.0 V power supply is connected across a 150.0 ohm, resistor in a series with an 160.0 ohm resistor. What is the potential drop across the 150.0 ohm resistor?

A. 4.8 V
B. 5.2 V
C. 11 V
D. 9.4 V

Answer 1

The potential drop across a 150.0 ohm resistor connected in series with a 160.0 ohm resistor and a 10.0 V power supply is 4.8 V.

Step-by-step explanation:

To determine the potential drop across the 150.0 ohm resistor connected in series with a 160.0 ohm resistor and a 10.0 V power supply, we first need to find the total resistance and then the current through the circuit. The total resistance (Rtotal) in series is the sum of both resistors: Rtotal = 150.0 ohms + 160.0 ohms = 310.0 ohms. Next, we use Ohm's law (V = IR) to find the current (I) flowing through the resistors: I = V / Rtotal = 10.0 V / 310.0 ohms ≈ 0.03226 A. Finally, to find the voltage drop across the 150.0 ohm resistor, we use Ohm's law again: V150 = I * R150 = 0.03226 A * 150.0 ohms ≈ 4.84 V, which we can round to 4.8 V to match the given answer choices.

Therefore, the correct answer is A. 4.8 V.