Question

A small glass bead has been charged to 8.0 mC. What is the strength of the electric field 2.0 cm from the center of the bead?

A. 1.8×10⁵ N/C
B. 1.4×10⁻³ N/C
C. 3.6×10⁻⁶ N/C
D. 3.6×10³ N/C

Answer 1

The strength of the electric field can be calculated using the equation E=kQ/r², where E is the electric field, k is the Coulomb's constant, Q is the charge, and r is the distance from the charge.

Step-by-step explanation:

The strength of the electric field due to a point charge can be calculated using the equation E=kQ/r², where E is the electric field, k is the Coulomb's constant (9x10^9 Nm²/C²), Q is the charge, and r is the distance from the charge. In this case, the charge is 8.0 mC (8.0x10^-3 C) and the distance is 2.0 cm (2.0x10^-2 m). Plugging in these values, we get E=(9x10^9 Nm²/C²)(8.0x10^-3 C)/(2.0x10^-2 m)². Solving this equation gives E=1.8x10^5 N/C, so the correct answer is A. 1.8x10^5 N/C.