Question

A force of 6 N acts on a charge of 3 mC when is is placed in a uniform electric field. What is the magnitude of this electric field

A. 18 N * mC
B. 2 N * mC
C. 0.5 mC / N
D. None of the above

Answer 1

The magnitude of the electric field can be found by dividing the force acting on a charge by the magnitude of the charge itself. In this case, the magnitude of the electric field is 2 N * mC.

Step-by-step explanation:

The magnitude of an electric field can be calculated by dividing the force acting on a charge by the magnitude of the charge itself. In this case, a force of 6 N acts on a charge of 3 mC. The magnitude of the electric field can be found using the formula: Electric field = Force / Charge. Plugging in the given values: Electric field = 6 N / 3 mC = 2 N * mC.

Therefore, the correct answer is B. 2 N * mC.